The volume of a gas-filled balloon is 30.0 L at 40 °C and 153 kPa pressure. What volume will the balloon have at standard temperature and pressure (273.15 K and 101.3 kPa) ?

a. 17.3 L

b. 23.7 L

c. 39.5 L

d. 51.9 L

A gas that has a volume of 28 liters, a temperature of 45 °C, and an unknown pressure, has its volume increased to 34 liters and its temperature decreased to 35 °C. If I measure the pressure after the change to be 2.0 atm, what was the original pressure of the gas?

a. 1.5 atm

b. 1.7 atm

c. 2.8 atm

d. 2.5 atm

Question

Chemistry

Sariah

7 March, 01:05

The volume of a gas-filled balloon is 30.0 L at 40 °C and 153 kPa pressure. What volume will the balloon have at standard temperature and pressure (273.15 K and 101.3 kPa) ?

a. 17.3 L

b. 23.7 L

c. 39.5 L

d. 51.9 L

A gas that has a volume of 28 liters, a temperature of 45 °C, and an unknown pressure, has its volume increased to 34 liters and its temperature decreased to 35 °C. If I measure the pressure after the change to be 2.0 atm, what was the original pressure of the gas?

a. 1.5 atm

b. 1.7 atm

c. 2.8 atm

d. 2.5 atm

+4

Answers (1)

Know the Answer?

Bruce Burke · Answer 1

1.) C

V1=30 L, T1=313.15K, P1=153kPa, V2=?, T2=273.15K, P2=101.3kPa

PV=nRT

(153) (30) = (n) (8.3145) (313.15)

(4590) = (n) (2603.685675)

n=1.7628856 moles

(101.3) (V2) = (1.7628856) (8.3145) (273.15)

(101.3) (V2) = (3917.023708)

V2=38.66755882 L

2.) D

V1=28L, T1=318K, P1=?, V2=34L, T2=308K, P2=2.0 atm

PV=nRT

(2.0) (34) = (n) (.08205) (308)

(68) = (n) (25.2714)

n = 2.690788797 mol

(P1) (28) = (2.690788797) (.08205) (318)

(P1) (28) = (70.20779221)

P=2.50742115 atm