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18 August, 11:01

A laboratory experiment requires 2.25 L of a 1.0 M solution of phosphoric acid (H3PO4), but the only available H3PO4 is a 9.0 M stock solution. How could you prepare the solution needed for the lab experiment? Show all the work used to find your answer.

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  1. 18 August, 13:07
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    The solution needed is prepared as below

    by use of the M1V1 = M2 V2 formula where

    M1 = 2.25 L

    v2 = 1.0M

    M2 = 9.0 M

    V2 = ? l

    make V2 the subject of the formula V2 = M1V1/M2

    = 2.25 L x 1.0M/9.0 M = 0. 25 L

    therefore the solution need 0.25 L of 9.0M H3PO4 and dilute it a final volume of 2.25 l
  2. 18 August, 13:56
    0
    We know that, M1V1 = M2V2

    (Initial) (Final)

    Given: M1 = 9.0 M

    M2 = 1.0 M

    V2 = 2.25 L

    Therefore we have, 9.0 x V1 = 1.0 x 2.25

    V1 = 0.25 L

    Thus, 0.25 L of stock solution (9.0 M), when diluted till 2.25 L, the resultant solution will have concentration 1.0 M.
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