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28 November, 17:46

Determine the [oh-] of a solution that is 0.260 m in hco-3.

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  1. 28 November, 18:37
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    HCO3^-1 hydrolysis will be HCO3^-1 + water = H2CO3 + OH - Kh = Kwater/k H2CO3 = 1*10^-14/4.4*10^-7 = 2.27 * 10^-8 Kh = [H2CO3][OH-]/[H2CO3-] 2.27 * 10^-8 = [X][X]/0.260 5.902 * 10^-9 = X² Therefore; X = {OH-] = 7.682 * 10^-5
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