In part a, we saw that the theoretical yield of aluminum oxide is 0.700 mol. calculate the percent yield if the actual yield of aluminum oxide is 0.329 mol.

The % yield is calculated as follows

% yield = actual yield / theoretical yield x100

theoretical yield = theoretical moles x molar mass

= 0.700 mole x 101.96 g/mol = 71.372 grams

actual mass = actual moles x molar mass

= 0.329 mol x 101.96 = 33.545 grams

% yield is therefore = 33.545/71.372 x100 = 47%