In a plant, 1,500 kg of nitrogen oxide is consumed per day to produce 1,500 kg of nitrogen dioxide per day. What is the percent yield?

Use.

Molecular weight of Nitrogen Oxide, NO

14g/mol N + 16g/mol O = 30 g/mol NO

Molecular weight Nitrogen Dioxide, NO2

14g/mol N + 2 (16g/mol O) = 46g/mol NO2

Calculate mole NO

1,500 kg * (1,000g / 1kg) * (1mol / 30 g NO) = 50,000 mol NO

Calculate theoretical yield for the product NO2; assuming 1:1 stoichiometry.

50,000 mol * (46 g / mol NO2) * (1kg / 1,000g) = 2,300 kg NO2

Percent yield = 100 * (actual yield / theoretical yield)

100 * (1,500kg / 2,300kg) = 65%