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Today, 08:39

A pure titanium cube has an edge length of 2.84 in how many titanium atoms does it contain? titanium has a density of 4.50g/cm3.

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  1. Today, 09:40
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    First let us assume that the shape of the Titanium is a perfect square so that the volume is calculated as:

    V = s^3

    V = (2.84 in) ^3

    V = 22.91 in^3

    Then calculate for the mass:

    m = (4.50 g/cm^3) * 22.91 in^3 * (2.54 cm/1in) ^3

    m = 1,689.15 g

    Calculating for the number of atoms by dividing with molar mass (47.87g/mol) and multiplying with Avogadros number:

    atoms = [ (1,689.15 g) / (47.87g/mol) ] * (6.022 x 10^23 atoms/mol)

    atoms = 2.125 x 10^25 atoms
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