What occurs when the temperature of 10.0 grams of water is changed from 15.5 degrees celsius to 14.5?

Q = m*Cp * (del T)

Where m = mass cp = specific heat capacity = 4.1855 J g-1 K-1 at 15 deg C del T = temp change = 14.5-15.5 = - 1 deg C

there fore, Q = 10*4.1855*-1 = - 41.855 J

Hence 42 joules will be release by water when temp is decrease from 15.5 to 14.5 deg C