The ph of 0.015 m hno2 (nitrous acid) aqueous solution was measured to be 2.63. what is the value of pka of nitrous acid?

Nitrous acid dissociates as follows:

HNO₂ (s) ⇄ H⁺ (aq) + NO₂⁻ (aq)

According to the equation, an acid constant has the following form:

Ka = [H⁺] * [NO₂⁻ ] / [HNO₂]

From pH, we can calculate the concentration of H⁺ and NO₂⁻:

[H⁺] = 10^-pH = 10^-2.63 = 0.00234 M = [NO₂⁻]

Now, the acid constant can be calculated:

Ka = 0.00234 x 0.00234 / 0.015 = 3.66 x 10⁻⁴

And finally,

pKa = - log Ka = 3.44