The oxygen gas produced in part a has a density of 1.43g/l. calculate the volume of of the o2 gas produced pg 76

The following is missing from the task above:

LiClO4 (s) →LiCl (s) + 2O2 (g)

m (LiClO4) = 100g

a) m (O2) = ?

From the reaction we got the following number of moles ratio:

n (LiClO4) : n (02) = 1 : 2

So, from the ratio, we can determine number of moles from O2:

n (02) = n (LiClO4) x 2 = (m/M) x 2 = 100/106.4 x 2 = 1.9 mole

Now we can calculate the mass of oxygen:

m (O2) = n x M = 1.9 x 32 = 60.15 g

b) V (O2) = ?

Now when we have the value of the mass of oxygen, we can calculate its volume with density equation:

d (O2) = m (O2) / V (O2) ⇒ V (O2) = m (O2) / d (O2)

V (O2) = 60.15 / 1.43

V (02) = 42.06 L