Ask Question
21 September, 18:24

For the reaction CO+2H2=CH3OH at 700 K, equilibrium concentrations are [H2]=0.072 M, [CO] = 0.020M, and [CH3OH] = 0.030 M. Calculate K

+1
Answers (1)
  1. 21 September, 22:12
    0
    The balanced equation for the reaction is

    CO (g) + 2H₂ (g) ⇄ CH₃OH (g)

    The given concentrations are at equilibrium state. Hence we can use them directly in calculation with the expression for the equilibrium constant, k. expression for k can be written as

    k = [CH₃OH (g) ] / [CO (g) ] [H₂ (g) ]²

    [H₂ ]=0.072 M

    [CO] = 0.020M

    [CH ₃OH] = 0.030 M

    From substitution,

    k = 0.030 M / 0.020 M x (0.072 M) ²

    k = 289.35 M⁻²

    Hence, equilibrium constant for the given reaction at 700 K is 289.35 M ⁻².
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “For the reaction CO+2H2=CH3OH at 700 K, equilibrium concentrations are [H2]=0.072 M, [CO] = 0.020M, and [CH3OH] = 0.030 M. Calculate K ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers