Magnesium is obtained from sea water. Ca (OH) 2 is added to sea water to precipitate Mg (OH) 2. The precipitate is filtered and reacted with HCl to produce MgCl2. The MgCl2 is electrolyzed to produce Mg and Cl2. If 185 g of magnesium are recovered from 962 g of MgCl2, what is the percent yield for this reaction? Answer in units of percent

Question

Chemistry

Marquise Hunter

22 August, 11:19

Magnesium is obtained from sea water. Ca (OH) 2 is added to sea water to precipitate Mg (OH) 2. The precipitate is filtered and reacted with HCl to produce MgCl2. The MgCl2 is electrolyzed to produce Mg and Cl2. If 185 g of magnesium are recovered from 962 g of MgCl2, what is the percent yield for this reaction? Answer in units of percent

+1

Answers (1)

Know the Answer?

Alivia Cain · Answer 1

Answer is: the percent yield for this reaction is 75,37%.

m (MgCl₂) = 962 g.

n (MgCl₂) = m (MgCl₂) : M (MgCl₂).

n (MgCl₂) = 962 g : 95,21 g/mol.

m (MgCl₂) = 10,1 mol.

n (MgCl₂) : n (Mg) = 1 : 1.

n (Mg) = 10,1 mol.

m (Mg) = 10,1 mol · 24,3 g/mol.

m (Mg) = 245,43 g.

ω (Mg) = 185 g : 245,43 g · 100% = 75,37%.