A compound composed of nickel and fluorine contains 9.11 g ni and 5.89 g f. what is the empirical formula of this compound

Empirical formula is the simplest formula showing the simplest ratio of atoms in a compound. Calculated as shown;

we start by calculating the number of moles of each atom;

moles of nickel = 9.11 g : 58.7 g = 0.155 moles

moles of fluorine = 5.89 g : 19 g = 0.31 moles

Then we get the ratio of the moles of nickel to that of flourine

That is 0.155 : 0.31 (dividing by the smallest)

0.155/0.155 : 0.31/0.155

we get 1:2 (the simplest ratio)

Therefore the empirical formula is nif2