A 5.0g sample of aluminum with a specific heat of 0.90 j/g was heated from 22.1^c to 32.1^c. How much heat to the nearest joule did the aluminum gain?

The heat to the nearest joules that aluminium gain is calculated as below

Q (heat) = M (mass) x c (specific heat capacity) x delta T (change in temperature)

M=5.0 g

c=0.90 j/g/c

deltat T = 32.1 - 22.1=10c

q = 5.0 g x 0.90 j/g/c x 10 c = 45 joules is the one gained by Alluminium