How many milliliters of a 5.0 M H2SO4 stock solution would you need to prepare 108.0 mL of 0.45 M H2SO4?

For the purpose we will use solution dilution equation:

c1xV1=c2xV2

Where, c1 - concentration of stock solution; V1 - a volume of stock solution needed to make the new solution; c2 - final concentration of new solution; V2 - final volume of new solution.

c1 = 5.00 M

c2 = 0.45 M

V1 = ?

V2 = 108 L

When we plug values into the equation, we get following:

5 x V1 = 0.45 x 108

V1 = 9.72 L