A chemical supply company sells sulfuric acid (H2SO4) in a concentration of 4.00 M. What volume of this solution would you need to make 12.0 mL of a 0.50 M H2SO4 solution? what is the volume needed?

Question

Howard Sherman

22 October, 15:03

+2

Answers (2)

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Alvin Wiggins · Answer 1

C₁=4.00 mol/L

c₂=0.50 mol/L

v₂=12.0 mL=0.012 L

n (H₂SO₄) = c₁v₁=c₂v₂

v₁=c₂v₂/c₁

v₁=0.50*0.012/4.00=0.0015 L = 1.5 mL

Cedric Colon · Answer 2

Equation: Vi=MfVf/Mi

mL of 4.00 M H2SO4: 1.5

Statement: Add 1.5 mL of 4.00 M H2SO4 to 10.5 mL of water to get 12 mL of 0.50 M H2SO4.