A neutral atom of neon has 10 electrons and an electron configuration of 1s2 2s2 2p6. How will it ionize to satisfy the octet rule?
A. It will lose 6 electrons from the 2nd energy level to have a valence configuration of 1s2 2s2.
B. It will lose 8 electrons from the 2nd energy level to have a valence configuration of 1s2.
C. It will gain 8 electrons in a 3rd energy level to have a valence configuration of 1s2 2s2 2p6 3s2 3p6.
D. It will not ionize; it already has an octet of electrons in its valence shell.
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