Determine the percent yield for the reaction between 3.74 g of na and excess o2 if 5.34 g of na2o2 is recovered.

Question

Chemistry

Cristian Chang

28 November, 23:19

Determine the percent yield for the reaction between 3.74 g of na and excess o2 if 5.34 g of na2o2 is recovered.

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Answers (1)

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Micaela Francis · Answer 1

Answer is: the percent yield for the reaction is 84,2%.

Chemical reaction: 2Na + O₂ → Na₂O₂.

m (Na) = 3,74 g.

n (Na) = m (Na) : M (Na).

n (Na) = 3,74 g : 23 g/mol.

n (Na) = 0,162 mol.

From chemical reaction: n (Na) : n (Na₂O₂) = 2 : 1.

n (Na₂O₂) = 0,162 mol : 2 = 0,081 mol.

m (Na₂O₂) = 0,081 mol · 78 g/mol.

m (Na₂O₂) = 6,341 g.

yield of reaction = 5,34 g / 6,341 g · 100%.

yield of reaction = 84,2%.