When 35 g of a metal at 94 ◦c is added to 51 g of water at 22 ◦c, the temperature of the water rises to 27 ◦c. what is the specific heat capacity of the metal?

M = mass of metal

M = mass of water

c = specific heat

c of water = 1 cal/g * C

use the formula

Q = mcΔT = McΔT

(27g) * (c) * (107 C - 27.3 C) = (54.2g) * (1 cal/g * C) * (27.3 C - 22 C)

2152 * c = 287.26

c = specific heat of metal =.133 cal/g * C

1 cal / 4.186 j/g * C =.133 cal / x

=.557 J/g * C