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8 January, 21:34

A sample of 54.0 g of methanol is heated from 25.0 °c to 35.0 °c. how much heat is required? the specific heat capacity of methanol is 2.48 j g-1 k-1.

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  1. 8 January, 22:47
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    The amount of heat required is calculated using the below formula

    Q (heat) = M (mass) xC (specific heat capacity) x delta T (change in temperature)

    change in the temperature in kelvin = (35+273) - (25 + 2730 = 10K

    c = 2.48 j/g/k

    mass = 54.0 g

    Q = 54.0 g x 2.48 j/g/k x 10k = 1339.2 joules is required
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