If the solubility of o2 at 0.370 atm and 25 °c is 15.3 g/100 g h2o, what is the solubility of o2 at a pressure of 2.40 atm and 25 °c?

According to Henry's law:

C = K P when,

C is the solubility of a gas at a constant temperature in a particular solvent.

K is the Henry law constant

p is the pressure of the gas

we have the pressure and the solubility so we will get the K at first:

by substitution:

0.153 = K * 0.37atm

K = 0.4

∴ C when P = 2.4 atm

∴ C = 0.37 * 2.4 atm = 0.888 = 88.8 g/100g H2O