What is the value of [oh-] in a 0.820 m solution of sr (oh) 2?

Strontium Hydroxide Ionizes as follow,

Sr (OH) ₂ → Sr²⁺ + 2 OH⁻

So,

1 mole of Sr (OH) ₂ produces 2 moles of Hydroxides,

If the concentration of 1 M Sr (OH) ₂ produces 2 M OH⁻ ions then, 0.082 M Sr (OH) ₂ will produce,

[OH⁻] = 2 * 0.082

[OH⁻] = 0.164 M