Ask Question
9 June, 03:01

An Olympic-size pool is 50.0 m long and 25.0 m wide.

a. How many gallons of water (density = 1.0 g/mL) are needed to fill the pool to an average depth of 4.8 ft?

b. What is the mass, in kg, of water in the pool?

+1
Answers (1)
  1. 9 June, 04:11
    0
    1. To calculate the volume of the pool you need to convert the length, width and height into one same unit. The volume would be:

    volume = length * width * height

    volume = 50m * 25m * (48ft * 0.3048m) = 18288m^3

    volume in gallons = 18288m^3 * (264.172 gallons/m^3) = 483.118 gallons

    2. The mass would be found by multiplying density with volume. You will need to some unit conversion to get the mass in kilogram. Remember that 1g = 1000kg and 1m^3 = 1,000,000ml

    mass = volume * density

    mass = 18288m^3 * (10^6 ml^3/m^3) * 1.0 g/mL / (1000g/kg) = 18,288,000 kg
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “An Olympic-size pool is 50.0 m long and 25.0 m wide. a. How many gallons of water (density = 1.0 g/mL) are needed to fill the pool to an ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers