Which of these are equal to 3.01 x 1023 particles 76.9 g of diatomic iodine (I2) 79.9 g of diatomic bromine (Br2) 6 g of carbon (C) 13.01 g of carbon tetahydride (CH4)

To determine which is the correct answer, we convert the mass of the compounds into units of particles of the compound. We use the molar masses and the Avogadro's number. We do as follows:

76.9 g I2 (1 mol / 253.81 g) (6.022x10^23 particles / 1 mol) = 1.82x10^23

79.9 g Br2 (1 mol / 159.81 g) (6.022x10^23 particles / 1 mol) = 3.011x10^23

6 g C (1 mol / 12 g) (6.022x10^23 particles / 1 mol) = 3.011x10^23

13.01 g CH4 (1 mol / 16.04 g) (6.022x10^23 particles / 1 mol) = 4.88x10^23 particles

Therefore, the answers are Br2 and C.