A piece of metal weighing 5.10 g at a temperature of 48.6 c was placed in a calorimeter in 20.00 ml of water at 22.1 degrees c the final equilibrium temperature was found to be 29.2 what is teh specific heat of the metal

Heat gained is equal to the heat lost;

Heat lost by metal = 5.10 * y * 19.4, where y is the specific heat capacity of the metal.

= 98.94 y

Heat gained by water = 20 g * 4.18 j/g * 7.1

= 593.56 Joules

Therefore; 98.94 y = 593.56

y = 593.56/98.94

= 5.99919 j/g

≈ 6.0 j/g

Therefore, the specific heat capacity of the metal is 6.0 J/g°C