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20 August, 06:30

If 100 ml of some pb (no3) 2 solution is mixed with 100 ml of 6.50 x 10-2 m nacl solution, what is the maximum concentration of the pb (no3) 2 solution added if no solid pbcl2 forms? (assume ksp = 2.00 x 10-5 m at this temperature.) enter the concentration in m.

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  1. 20 August, 07:04
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    Suppose X (in unit M) be the required maximum concentration of the Pb (NO₃) ₂ solution added after mixing with 100 ml of 6.5 x 10⁻² M NaCl, the Pb²⁺ concentration is:

    [Pb²⁺] = (X*100) / 200 = 0.5 X

    The concentration of Cl⁻ is:

    [Cl⁻] = (100 / 200) * (6.5 x 10⁻² M) = 0.0325 M

    So:

    Ksp = 2.00 x 10⁻⁵ = [Pb²⁺] [Cl⁻]² = (0.5X) * (0.0325) ²

    X = (2.00 x 10⁻⁵) / (5.28 x 10⁻⁴) = 0.038 M
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