A 55-mL solution of H2SO4 is completely neutralized by 46 mL of 1.0M NaOH. What is the concentration of the H2SO4∆H2SO4 (aq) + 2NaOH (aq) → Na2SO4 (aq) + 2H2O (l)

H₂SO₄ + 2NaOH = Na₂SO₄ + 2H₂O

v (NaOH) = 46 ml=0.046 l

c (NaOH) = 1.0 mol/l

v (H₂SO₄) = 55 ml=0.055 l

n (NaOH) = v (NaOH) * c (NaOH)

n (H₂SO₄) = 0.5n (NaOH)

c (H₂SO₄) = n (H₂SO₄) / v (H₂SO₄) = 0.5*v (NaOH) * c (NaOH) / v (H₂SO₄)

c (H₂SO₄) = 0.5*0.046*1.0/0.055=0.418 mol/l

The concentration of the H₂SO₄ is 0.418M.