A solution is prepared by dissolving 15.0 g of nh3 in 250.0 g of water. the density of the resulting solution is 0.974 g/ml. the molality of nh3 in the solution is

The formula for molality---> m = moles solute / Kg of solvent

the solute here is NH₃ because it's the one with less amount. which makes water the solvent.

1) let's convert the grams of NH₃ to moles using the molar mass

molar mass of NH₃ = 14.0 + (3 x 1.01) = 17.03 g / mol

15.0 g (1 mol / 17.03 g) = 0.881 mol NH₃

2) let's convert the grams of water into kilograms (just divide by 1000)

250.0 g = 0.2500 kg

3) let's plug in the values into the molality formula

molality = mol / Kg---> 0.881 mol / 0.2500 kg = 3.52 m