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5 June, 04:03

Which compound (s will not form a yellow precipitate when treated with excess iodine in the presence of naoh?

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  1. 5 June, 05:54
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    For example:

    5Cl₂ + I₂ + 12NaOH = 10NaCl + 2NaIO₃ + 6H₂O

    Na₂S₂O₃ + 4I₂ + 10NaOH = 8NaI + 2Na₂SO₄ + 5H₂O
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