What volume will a balloon occupy at 1.0 atm, if the balloon has a volume of 4.4 l at 2.2 atm?

The two states of the balloon are

State 1:

pressure, p₁ = 1 atm = 101325 Pa

State 2:

volume, V₂ = 4.4 L = 4.4*0.001 m³ = 0.0044 m³

pressure, p₂ = 2.2 atm = 2.2*101325 Pa = 222915 Pa

Let V₁ = the volume in state 1.

Assume that the air in the balloon is at the same temperature at the two given states.

Then according to Boyle's Law (pV = constant), obtain

(101325 Pa) * (V₁ m³) = (222915 Pa) * (0.0044 m³)

V₁ = 0.00968 m³

= (0.00968 m³) / (0.001 m³/L) = 9.68 L

Answer: 9.68 L