Zn (s) + cu2 + (aq) →zn2 + (aq) + cu (s). part a under standard conditions, what is the maximum electrical work, in joules, that the cell can accomplish if 51.0 g of copper is plated out?

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3 January, 02:56

Zn (s) + cu2 + (aq) →zn2 + (aq) + cu (s). part a under standard conditions, what is the maximum electrical work, in joules, that the cell can accomplish if 51.0 g of copper is plated out?

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Kelsey · Answer 1

The energy in Joules is calculated as:

E = VQ

At standard conditions, the standard potential or the voltage is equal to 0.76 V. Next, we have to determine Q. The formula is as follows:

Q = nF, where n is the number of moles electron, while F is the Faraday's constant (96,500 C/mol e)

From the given reaction, notice that Zn was converted to Zn²⁺, while Cu²⁺ to Cu. So, 1 mol Cu = 2 mol e.

Q = 51 g Cu (1 mol Cu/63.55 g) (2 mol e/1 mol Cu) (96,500 C/mol e)

Q = 154885.92 C

Thus,

E = (0.76 V) (154885.92 C)

E = 117,713.3 J