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27 February, 06:56

A 0.100-g sample of your favorite candy is burned in a calorimeter that contains 1.00 kg of water initially at 21.0 ∘C. After the candy is burned, the water temperature is 34.5 ∘C. How many Calories are there per gram of your candy?

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  1. 27 February, 09:28
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    Answer: 565.245kJ

    To answer this question, you need to know how much water heat capacity which was 4.187 kJ/kg K. First, we need to find the calorie absorbed by water. Since the sample is 1kg, the initial temperature is 21 ∘C and final temperature is 34.5 ∘C then the calculation would be:

    Energy = (Final temp - initial temp) * heat capacity * mass

    Energy = (34.5-21) ∘C * 4.187 * kJ/kg K * 1kg = 56.5245 kJ

    The energy is made from 0.1 gram, then for 1 gram of energy it should be:

    1 gram / 0.1gram x 56.5245 kJ = 565.245kJ
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