The standard reaction free energy = δg0-311. kj for this reaction: p4 (s) + 20hf (g) → 4pf5 (g) + 10h2 (g) use this information to complete the table below. round each of your answers to the nearest kj.

Answers are:

Standard reaction: P₄ + 20HF→ 4PF₅ + 10H₂.

1) chemical reaction: 1/5P₄ + 4HF→ 4/5PF₅ + 2H₂.

ΔG = - 311kJ : 5 = - 62,2 kJ.

2) chemical reaction: 12PF₅ + 30H₂ → 3P₄ + 60HF.

ΔG = - 311kJ · (-3) = 933 kJ.

3) chemical reaction: 4PF₅ + 10H₂ → P₄ + 20HF.

ΔG = - 311kJ · (-1) = 311 kJ, reversed standard reaction.