Consider the reaction: 2 al (s) + 3 cl2 (g) → 2 alcl3 (s) a chemist reacts 0.50 mol of aluminum with 0.80 mol of chlorine. if the limiting reactant is determined to be aluminum, what is the theoretical yield of aluminum chloride in moles?

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Chemistry

Niki

26 October, 01:27

Consider the reaction: 2 al (s) + 3 cl2 (g) → 2 alcl3 (s) a chemist reacts 0.50 mol of aluminum with 0.80 mol of chlorine. if the limiting reactant is determined to be aluminum, what is the theoretical yield of aluminum chloride in moles?

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Anne Carlson · Answer 1

0.5 mol The chemical formula give shows that for every 2 mols of Al, 2 mols of AlCl3 is produced. That is a one to one ratio. Since 0.5 mols of aluminum is provided. 5 mols of AlCl3 results.