N2 + 3 H2 - > 2 NH3

How many mols of N2 will be produced if it reacts with 2.5 x 1021 molecules of N2

N2 + 3H2 = 2NH3

First, we need to determine the number of N2 moles:

n (N2) = N/NA = 2.5 x 10²¹ / 6x10²³ = 0.0042 mole

According to the equation of the reaction of ethane combustion, nitrogen and ammonia have following stoichiometric ratio:

n (N2) : n (NH3) = 1 : 2

n (NH3) = 2xn (N2)

n (NH3) = 2x0.0042 = 0.0083 mole of NH3 will be produced in the reaction