Based on a kc value of 0.200 and the given data table, what are the equilibrium concentrations of xy, x, and y, respectively? express the molar concentrations numerically.

Missing in your question:

Concentration by (M):

Xy: y: X

initial 0.2 0.3 0.3

change + X - X - X

equilibrim (0.2+x) (0.3-x) (0.3-x)

according to Kc formula: when Kc = 0.2

Kc = [XY]/[X]*[Y]

0.2 = (0.2+x) / (0.3-x) * (0.3-x)

0.2 = (0.2+x) / (0.3-x) ^2 by solving this equation

0.2 * (0.3-x) ^2 = 0.2+x

0.2 * (0.09-0.6x+x^2) = 0.2 + x

0.0018 - 0.12 X + 0.2X^2 = 0.2 + X

0.2X^2 - 1.12 X - 0.1982 = 0

∴X = 0.17

∴[XY] = 0.2 + 0.17 = 0.37 m

∴[X] = 0.3 - 0.17 = 0.13 m

∴[y] = 0.3 - 0.17 = 0.13 m