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31 May, 19:03

What is the volume of 0.110 g of c2h2f4 vapor at 0.575 atm and 34.8◦c? answer in units of l?

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  1. 31 May, 22:14
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    To calculate the volume of the gas, we can use the ideal gas law equation.

    PV = nRT

    P - pressure - 0.575 atm x 101 325 Pa/atm = 58 261.9 Pa

    V - volume

    n - number of moles

    C₂H₂F₄ - molar mass - 102 g/mol

    Number of moles - 0.110 g / 102 g/mol = 0.00108 mol

    R - universal gas constant - 8.314 Jmol⁻¹K⁻¹

    T - temperature in Kelvin - 34.8 °C + 273 = 307.8 K

    Substituting values in the equation,

    58 261.9 Pa x V = 0.00108 mol x 8.314 Jmol⁻¹K⁻¹ x 307.8 K

    V = 0.0000474 m³

    V = 0.0474 L
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