Label each reactant and product in this reaction as a bronsted acid or base. CH3OH + OH - CH3O - + H2O

In Bronsted acid base theory,

acids are proton (H+) donors

bases are proton (H+) acceptors.

At the reaction, CH3OH (methly alcohol) donates one H + to OH - ions (hydroxide). So that OH - becomes H2O with an extra H atom. (+) charge neutralizes (-) charge of ion. Notice that H2O is neutral.

Since CH3OH lose one positive H atom, it becomes CH3O-.

Donor is CH3OH, so it is the acid and its conjugate base is CH3O-

Acceptor is OH-, so it the base and its conjugate acid is H2O.