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5 March, 07:48

At a certain temperature, the equilibrium constant, kc, for this reaction is 53.3. at this temperature, 0.500 mol of h2 and 0.500 mol of i2 were placed in a 1.00-l container to react. what concentration of hi is present at equilibrium?

equation: h2 + i2 = 2hi

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  1. 5 March, 11:07
    0
    When the balanced equation for the reaction is:

    H2 (g) + i2 (g) ⇄ 2Hi

    initial 0.5 0.5 X

    -X - X + X

    Final (0.5-x) (0.5-x) 2X

    by substitution at the Kc formula:

    Kc = [Hi]^2 / [H2] * [i2]

    53.3 = (2X) ^2 / (0.5-X) (0.5-X) by taking the square route

    √53.3 = 2X / (0.5-X)

    ∴X = 0.39 m

    ∴[Hi] = 0.39 m
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