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7 May, 08:32

How many grams of cucl2 are required to prepare 1250. g of a 1.25% (by mass) cucl2 solution?

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  1. 7 May, 09:35
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    The grams of CuCl2 required to prepare 1250g of 1.25% by mass is calculated as follow

    1250 = 100%

    what about 1.25%

    by cross multiplication

    = 1.25 x1250/100 = 15.63 grams
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