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5 October, 20:38

If 5400. Joules of energy were supplied to 4.5 grams of ice at - 10 degree Celsius, how many grams of what phases would you have?

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  1. 5 October, 22:08
    0
    The answers to you questions are 3,66 g of liquid water and 0,84 g of vapor.

    Solution:1) Q₁ = mxCxΔT = 4,5 g x 2,108 J/°C x g x 10°C.

    = 97,86 J heat required to warm the ice to 0°C.

    2) = 4,5 g x 334 J/g. = 1503 J heat required to melt the ice to water at 0°C.

    3) = 4,5 g x 4,184 J/°C x g x 100°C

    = 1882,28 J heat required to warm the water from 0°C to 100°C. = 5400 J - 3483,14 J = 1916,86 J heat left to vaporize the water.

    mass of the vapor = 1916,86 J : 2257 J/g

    = 0,84 g.
  2. 5 October, 23:42
    0
    Answer is: 3,66 g of liquid water and 0,84 g of vapor.

    1) Q₁ = m·C·ΔT

    Q₁ = 4,5 g · 2,108 J/°C·g · 10°C.

    Q₁ = 97,86 J heat required to warm the ice to 0°C.

    2) Q₂ = 4,5 g · 334 J/g.

    Q₂ = 1503 J heat required to melt the ice to water at 0°C.

    3) Q₃ = 4,5 g · 4,184 J/°C·g · 100°C

    Q₃ = 1882,28 J heat required to warm the water from 0°C to 100°C.

    Q₄ = 5400 J - 3483,14 J = 1916,86 J heat left to vapourize the water.

    m (vapor) = 1916,86 J : 2257 J/g = 0,84 g.
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