What is the empirical formula for a compound that is 50.8 zinc 16.0 phosphorus and 33.2 oxygen

1) number mole in

50.8 g Zn * (1 mol Zn/65.4g) = 0.777 mol Zn

2) number mole in

16.0 g P * (1 mol P/31.0 g) = 0.516 mol P

3) number mole in

33.2 g O * (1 mol O/16.0 g) = 2.075 mol O

0.777 mol Zn : 0.516 mol P : 2.075 mol O =

= (0.777 mol Zn/0.516) : (0.516 mol P/0.516) : (2.075 mol O/0.516) =

=1.5 mol Zn : 1 mol P : 4 mol O=3 Zn : 2 P : 8O

Zn3P2O8

or

the same is Zn3 (PO4) 2