What volume of hydrogen gas can be produced by reacting 4.20 g of sodium in excess water at 50.0 Celsius and 106 kPa? The reaction is 2Na + 2H20 - - > 2NaOH + H2.

Question

Chemistry

Finnegan

22 March, 00:03

What volume of hydrogen gas can be produced by reacting 4.20 g of sodium in excess water at 50.0 Celsius and 106 kPa? The reaction is 2Na + 2H20 - - > 2NaOH + H2.

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Chana Simon · Answer 1

From the equation, you can conclude that 2 Natrium atoms will form 1 H2 molecule. Then, the number of hydrogen molecules formed by 4.2g of sodium would be:4.2g / (23g/mol) * 1/2 = 0.0913 mol.

Using the ideal gas formula, the volume of the gas would be:

V = nRT/P

V = (0.0913 mol * 8.314 L-kPa/mol-K * 323K) / 106 kPa

V = 2.3131 L