What is the temperature of 12.2 moles gas in a 18.35 l tank at 16.4 atm? express in K and C.

This problem can be solved by using ideal gas equation PV=nRT. The unit used in the pressure is kPa so you will need to convert it. The temperature also use Kelvin, you will need to convert it if you want it in C.

The calculation would be:

PV = nRT

16.4 atm * (101.35kPa/atm) * 18.35 L = 12.2 mol * T * (8.314 L*kPa/mol*K)

T=30500 / 101.4308

T = 300.70 °K = 27.55 °C