Ask Question
2 May, 16:37

A liquid was analyzed to be 54.5% c, 9.10% h, and 36.4% o. an empty flask, whose mass was 45.32 g, when filled with the vapor of the liquid at 735mm hg and 99.2°c had a mass of 46.05 g. the volume of the flask was found to be 263.2 ml. type your answers using the format ch4 for ch4. enter the elements in the order given. what is the empirical formula of the compound? c2h4o correct: your answer is correct. what is the molecular formula of the compound?

+4
Answers (1)
  1. 2 May, 20:34
    0
    number Moles of C = 54.5 g / 12.011 = 4.54 number Moles of H = 9.10 / 1.008 = 9.02 number Moles of O = 36.4 / 16 = 2.28 if we want to divide by the smallest number 4.54 / 2.28 = 2 = > C 9.02 / 2.28 = 4 = > H 2.28 / 2.28 = 1 = > O Empirical formula will be = C2H4O
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A liquid was analyzed to be 54.5% c, 9.10% h, and 36.4% o. an empty flask, whose mass was 45.32 g, when filled with the vapor of the liquid ...” in 📘 Chemistry if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers