The reaction of hydrazine (n2h4) with chlorine trifluoride (clf3) has been used in experimental rocket motors. n2h4 (g) + 4/3 clf3 (g) 4 hf (g) + n2 (g) + 2/3 cl2 (g) (kp) how is the equilibrium constant, kp, for this reaction related to kp' for the reaction written this way?

Question

Chemistry

Kelly Paul

24 March, 15:58

The reaction of hydrazine (n2h4) with chlorine trifluoride (clf3) has been used in experimental rocket motors. n2h4 (g) + 4/3 clf3 (g) 4 hf (g) + n2 (g) + 2/3 cl2 (g) (kp) how is the equilibrium constant, kp, for this reaction related to kp' for the reaction written this way?

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Karsyn Boyle · Answer 1

Answer is: the equilibrium constant is (Kp) ³ = Kp '.

N₂H₄ (g) + 4/3ClF₃ (g) → 4HF (g) + N₂ (g) + 2/3Cl₂ (g) (Kp).

3N₂H₄ (g) + 4ClF₃ (g) → 12HF (g) + 3N₂ (g) + 2Cl₂ (g) (Kp ').

Second reaction was multiply with 3. The equilibrium constant is a ratio of the concentration of the products to the concentration of the reactants.