The data in the table below were obtained for the reaction: 2clo2 (aq) + 2 oh - (aq) - - > clo3 - (aq) + clo2 - (aq) + h2o (l) experiment [clo2] (m) [oh-] (m) initial rate (m/s) 1 0.060 0.030 0.0248 2 0.020 0.030 0.00276 3 0.020 0.090 0.00828 what is the order of the reaction with respect to clo2?

Lets organise the data given in the question

[ClO₂] (m) [OH⁻] (m) initial rate (m/s)

0.060 0.030 0.0248

0.020 0.030 0.00276

0.020 0.090 0.00828

rate equation as follows

rate = k [ ClO₂]ᵃ [OH⁻]ᵇ

where k - rate constant

we need to find order with respect to ClO₂ therefore lets take the 2 equations where OH⁻ is constant.

1) 0.00276 = k [0.020]ᵃ[0.030]ᵇ

2) 0.0248 = k [0.060]ᵃ[0.030]ᵇ

divide first equation from the second

0.0248/0.00276 = [0.060/0.020]ᵇ

8.99 = 3ᵇ

8.99 rounded off to 9

9 = 3ᵇ

b = 2

order with respect to ClO₂ is 2