Determine the grams of oxygen gas that reacts with 1.75 moles of hydrogen gas

The reaction between Hydrogen and Oxygen under normal conditions is characterized by the following balanced equation:

2 H₂ + O₂ → 2 H₂O

The mole ratio (based on the coefficient used to balance the chemical equation) of H₂ : O₂ is 2 : 1.

Thus there are two times as many moles of H₂ in the reaction as there are moles of O₂.

∴ if the moles of H₂ = 1.75 mol

then the moles of O₂ = 1.75 mol : 2

= 0.875 mol

Now, Mass = Moles * Molar Mass

Thus the mass of oxygen gas = 0.875 mol * 32 g/mol = 28 g

Thus the answer is 28 grams.