When aluminum is placed in concentrated hydrochloric acid, hydrogen gas is produced. what volume of h2 is produced when 7.20 g of al reacts at stp?

2Al + 6HCl = 2AlCl₃ + 3H₂

m (Al) = 7.20 g

Vm = 22.4 L/mol

M (Al) = 27.0 g/mol

n (Al) = m (Al) / M (Al)

n (H₂) = 3n (Al) / 2

V (H₂) = Vm n (H₂) = 3Vm n (Al) / 2 = 3Vm m (Al) / {2M (Al) }

V (H₂) = 3*22.4*7.20/{2*27.0}=8.96 L