The ksp for silver (i) phosphate is 1.8 x 10 - 18. determine the silver ion concentration in a saturated solution of silver (i) phosphate

The silver ion concentration in saturated solution of silver (i) phosphate is calculated as follows.

write the equation for dissociation of silver (i) phosphate

that is Ag3PO4 (s) = 3Ag^ + (aq) + PO4 ^3 - (aq)

let the concentration of the ion be represented by x

ksp is therefore = (3x^3) (x) = 1.8 x10 ^-18

27 x^3 (x) = 1.8 x10^-18

27x^4 = 1.8 x10^-18 divide both side 27

X^4 = 6.67 x10 ^-20

find the fourth root x = 1.6 x10 ^-5m

the concentration of silver ion is therefore = 3 x (1.6 x10^-5) = 4.8 x10^-5m