Tori wants to increase the temperature of 500 grams of water from 20 c to 100 c if the specific heat of water is 4.18 j g c how much heat is needed

The heat needed is calculated as follows

Q = mc delta T

m = mass = 500g

c = specific heat capacity = 4.18 j g c

delta T = change in temperature 100 - 20 = 80 c

Q is therefore = 500g x 4.18 j g c x 80 c = 167,200j or in Kj = 167200/1000=167.2 kj